SOLUTION: 6x^2-19x+10=0

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Question 520679: 6x^2-19x+10=0
Answer by Math_prodigy(24) About Me  (Show Source):
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a=6, b=-19, c=10
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-19%29+%2B-+sqrt%28+%28-19%29%5E2-4%2A6%2A10+%29%29%2F%282%2A6%29+
x=(19+11)/12=30/12=5/2
x=(19-11)/12=8/12=2/3
Answer 5/2 and 2/3