Question 515854: What are the steps that you would take to factor out 2x^2+x+3
Answer by drumwrrv(7)   (Show Source):
You can put this solution on YOUR website! 2x^(2)+x+3=0
Use the quadratic formula to find the solutions. In this case, the values are a=2, b=1, and c=3.
x=(-b\~(b^(2)-4ac))/(2a) where ax^(2)+bx+c=0
Substitute in the values of a=2, b=1, and c=3.
x=(-1\~((1)^(2)-4(2)(3)))/(2(2))
Simplify the section inside the radical.
x=(-1\i~(23))/(2(2))
Simplify the denominator of the quadratic formula.
x=(-1\i~(23))/(4)
First, solve the + portion of \.
x=(-1+i~(23))/(4)
Next, solve the - portion of \.
x=(-1-i~(23))/(4)
The final answer is the combination of both solutions.
x=(-1+i~(23))/(4),(-1-i~(23))/(4)
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