SOLUTION: 1/2(4x-8y+10)+3(2x+y-1)

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Question 507136: 1/2(4x-8y+10)+3(2x+y-1)
Answer by Maths68(1474) About Me  (Show Source):
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1/2(4x-8y+10)+3(2x+y-1)
=(4x-8y+10)/2+3(2x+y-1)
=2(2x-4y+5)/2+(6x+3y-3)
=(2x-4y+5)+(6x+3y-3)
=2x-4y+5+6x+3y-3
=8x-y+2