SOLUTION: 1/(2*x-6)+2/(3*x-9)=7/(x^2-3*x) I LOVE this site~!! Thanks for the help:) Chris

Algebra ->  Equations -> SOLUTION: 1/(2*x-6)+2/(3*x-9)=7/(x^2-3*x) I LOVE this site~!! Thanks for the help:) Chris      Log On


   

Question 50655: 1/(2*x-6)+2/(3*x-9)=7/(x^2-3*x)
I LOVE this site~!! Thanks for the help:)
Chris
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
This is a fractional equation. Start by factoring the denominators so you can find the LCD for the problem.
1%2F%282%28x-3%29%29+%2B+2%2F%283%28x-3%29%29+=+7%2F%28x%28x-3%29%29+

The LCD = 6x(x-3), so multiply both sides of the equation by the LCD. It's ugly at first, but in the first step all the fractions divide out!
1%2F%282%28x-3%29%29+%2B+2%2F%283%28x-3%29%29+=+7%2F%28x%28x-3%29%29+


After all the denominator factors divide out, this is what is left:
3x+%2B+4x+=+42
7x+=+42
x+=+6

One more step: Check each denominator, and make sure that x= 6 doesn't make any denominators zero. Also, you can check the answer by substituting x= 6 into the original equation (if you want to go to some trouble).

R^2 at SCC