SOLUTION: I need help with this. I don't know where to begin. Factor: -1x^2+6xy+9y^2

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Question 48519: I need help with this. I don't know where to begin.
Factor: -1x^2+6xy+9y^2
Found 2 solutions by checkley71, cowess:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
using the quadratic equation x=[(-b+/-sqrt(b~2-4ac)]/2a

we get (x-7.2426y)(x+1.2426y)

Answer by cowess(34) About Me  (Show Source):
You can put this solution on YOUR website!
Two ways of doing this, I think the second one will do better.
First way:
a trigonomial can be written like ax^2+bx+c
f(x)=-1x^2+6xy+9y^2
a=-1
b=6y
c=9y^2
if f(x)=0
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a
x=3y%281%2B-sqrt%282%29%29
f%28x%29=-%28x-3y%281%2Bsqrt%282%29%29%29%28x-3y%281-sqrt%282%29%29%29
Second way:
f%28x%29=-1x%5E2%2B6xy%2B9y%5E2
=18y%5E2-%28x%5E2-6xy%2B9y%5E2%29
=%28%283sqrt%282%29%29y-%28x-3y%29%29%28%283sqrt%282%29%29y%2B%28x-3y%29%29
=%28%283sqrt%282%29%29y-%28x-3y%29%29%28%283sqrt%282%29%29y%2B%28x-3y%29%29
=%283y%28sqrt%282%29%2B1%29-x%29%283y%28sqrt%282%29-1%29%2Bx%29