SOLUTION: I know this is pretty simple but its slipped my mind, how do you solve for the product of an equations like these: (x-4)(x+3) ; (3x-2)(2x-5) ; (4x-3)(x^2+2x-5) ??? I just completel

Algebra ->  Equations -> SOLUTION: I know this is pretty simple but its slipped my mind, how do you solve for the product of an equations like these: (x-4)(x+3) ; (3x-2)(2x-5) ; (4x-3)(x^2+2x-5) ??? I just completel      Log On


   

Question 482125: I know this is pretty simple but its slipped my mind, how do you solve for the product of an equations like these: (x-4)(x+3) ; (3x-2)(2x-5) ; (4x-3)(x^2+2x-5) ??? I just completely blanked on these.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first one to get you started




%28x-4%29%28x%2B3%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%28x%29-4%29%28highlight%28x%29%2B3%29 Multiply the First terms:%28x%29%2A%28x%29=x%5E2.


%28highlight%28x%29-4%29%28x%2Bhighlight%283%29%29 Multiply the Outer terms:%28x%29%2A%283%29=3%2Ax.


%28x%2Bhighlight%28-4%29%29%28highlight%28x%29%2B3%29 Multiply the Inner terms:%28-4%29%2A%28x%29=-4%2Ax.


%28x%2Bhighlight%28-4%29%29%28x%2Bhighlight%283%29%29 Multiply the Last terms:%28-4%29%2A%283%29=-12.


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So we have the terms: x%5E2, 3%2Ax, -4%2Ax, -12


x%5E2%2B3%2Ax-4%2Ax-12 Now add every term listed above to make a single expression.


x%5E2-x-12 Now combine like terms.


So %28x-4%29%28x%2B3%29 FOILs to x%5E2-x-12.


In other words, %28x-4%29%28x%2B3%29=x%5E2-x-12.