SOLUTION: If c = 18a + 24b, where a and b are positive integers, then c must be divisible by which of the following?
a) 4
b) 6
c) 9
d) 12
e) 72
Than you!!! :-)
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-> SOLUTION: If c = 18a + 24b, where a and b are positive integers, then c must be divisible by which of the following?
a) 4
b) 6
c) 9
d) 12
e) 72
Than you!!! :-)
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Question 479613: If c = 18a + 24b, where a and b are positive integers, then c must be divisible by which of the following?
a) 4
b) 6
c) 9
d) 12
e) 72
Than you!!! :-) Answer by Edwin McCravy(20055) (Show Source):
18a + 24b
by the distributive principle (used in reverse)
6(3a + 8b)
Therefore it must be divisible by 6
An easy counter-example for the others is when a = 1, and b = 1
c = 18a + 24b = 18(1) + 24(1) = 18 + 24 = 42 which is
not divisible by 4, 9, 12, or 72
Edwin
