Question 475188: PLEASE solve these problems PLEASE !!
log(3)5+log(3)x=log(3)10
log(1/7)x=-1
2ln3x+1=5
log(3)0.1+2log(3)x=log(3)2+log(3)5
log(b)9=2
1/4log(2)16+1/2log(2)49=log(2)2x
3^2m=16^-1
4^ex-5=1
THESE ARE THE ANSWER CHOICES :
2 , 5 , 14 , -2 , 3.2147 , 10 , 7 , 1.0986 , 0.5537 , 4 , 2.4630 , 3
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! log(3)5+log(3)x=log(3)10
Adding logs --> multiply
5x = 10
x = 2
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log(1/7)x=-1
Is that log of (x/7) ? or log or x*log(1/7) ?
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2ln3x+1=5
2ln(3x) = 4
ln(3x) = 2
3x = e^2
x = e^2/3
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log(3)0.1+2log(3)x=log(3)2+log(3)5
Similar to the 1st one.
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log(b)9=2
b^2 = 9
b = 3
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1/4log(2)16+1/2log(2)49=log(2)2x
Similar to the 1st one.
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3^2m=16^-1
Is 2 the exponent? or 2m?
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4^ex-5=1
4^ex = 6x
ex = 6^(1/4)
x = 6^(1/4)/e
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