SOLUTION: Please solve these .
*WHEN I PUT LOG(3) THAT IS A SUBSCRIPT *
LOG(3)5+LOG(3)X=LOG(3)10
LOG(1/7)X=-1
2LN3X+1=5
LOG(3)0.1+2LOG(3)5
LOG(B)9=2
1/4LOG(2)16+1/2LOG(2)49=LOG(2)X
Algebra ->
Equations
-> SOLUTION: Please solve these .
*WHEN I PUT LOG(3) THAT IS A SUBSCRIPT *
LOG(3)5+LOG(3)X=LOG(3)10
LOG(1/7)X=-1
2LN3X+1=5
LOG(3)0.1+2LOG(3)5
LOG(B)9=2
1/4LOG(2)16+1/2LOG(2)49=LOG(2)X
Log On
Question 474722: Please solve these .
*WHEN I PUT LOG(3) THAT IS A SUBSCRIPT *
LOG(3)5+LOG(3)X=LOG(3)10
LOG(1/7)X=-1
2LN3X+1=5
LOG(3)0.1+2LOG(3)5
LOG(B)9=2
1/4LOG(2)16+1/2LOG(2)49=LOG(2)X
3^N-2=27
2^2N=16^-1
4^3X=10
2^EX-5=1
These are the answer choices :
14
3
-2
2.4630
2
3.2147
7
4
1.0986
0.5537
10
5 Answer by Alan3354(69443) (Show Source):
