SOLUTION: factor completely 20n^4-22n^3-12n^2

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Question 47237: factor completely
20n^4-22n^3-12n^2
Answer by checkley71(8403) About Me  (Show Source):
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20n~4-22n~3-12n~2=0 or 2n~2(10n~2-11n-6)=0 or 2n~2(5x+2)(2x-3)=0 then 2n~2-0 or n=0 & 5n+2=0 or 5n=-2 or n=-.4 & 2n-3=0 or or 2n=3 or n=3/2 or n=1.5