SOLUTION: The lenght of a rectangle is 2 in. more than 8 times its width. If the area of the rectangle is 210 sq.in, find the dimensions of the rectangle.

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Question 47008: The lenght of a rectangle is 2 in. more than 8 times its width. If the area of the rectangle is 210 sq.in, find the dimensions of the rectangle.
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = 8w + 2
AREA+=+lw
210+=+8w%5E2+%2B+2w
0+=+8w%5E2+%2B+2w+-+210
0+=+4w%5E2+%2B+w+-+105
0+=+4w%5E2+%2B+21w+-+20w+-+105
0+=+%284w%5E2+%2B+21w%29+%2B+%28-20w+-+105%29
0+=+w%284w+%2B+21%29+-+5%284w+%2B+21%29
0+=+%28w+-+5%29%284w+%2B+21%29
Since a measure ment can not be negative, your width is:
w - 5 = 0
w = 5
length = 8w + 2 = 42