SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -(x+8)^2-3

Algebra ->  Equations -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -(x+8)^2-3      Log On


   



Question 464950: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x) = -(x+8)^2-3
Found 2 solutions by ewatrrr, Gogonati:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex
f(x) = -(x+8)^2-3 |V(-8,-3), a = -1 <0 ,parabola opens downward, vertex a max Pt
x = -8, line of symmetry


Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
The function f%28x%29=-%28x%2B8%29%5E2-3 represent a downward parabola with vertex
(-8, -3), line of symmetry x=-8, and maximum value y=-3. See the graph below:
graph%28300%2C+300%2C+-15%2C+3%2C+-10%2C+3%2C+-%28x%2B8%29%5E2-3%29.