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x + 2 x - 4 8(x + 1)
————— + ————— + ————————
x - 7 7 - x x - 7
We must get all the denominators the same.
Two of the denominators are already the same,
but the 7 - x is not the same. So let's work
on it:
7 - x
First write it in descending order:
-x + 7
which is really
-1x + 7
Now factor out -1 (which changes the sign of the 7)
-1(x - 7)
and we can erase the 1
-(x - 7)
Now our original problem becomes:
x + 2 x - 4 8(x + 1)
————— + —————— + ————————
x - 7 -(x - 7) x - 7
Now take the - sign out in front of
that fraction making the + into a -
x + 2 x - 4 8(x + 1)
————— - ————— + ————————
x - 7 x - 7 x - 7
Now all the denominators are the same.
Distribute out the 8(x + 1) as 8x + 8
x + 2 x - 4 8x + 8
————— - ————— + ————————
x - 7 x - 7 x - 7
Put parentheses around the numerators:
(x + 2) (x - 4) (8x + 8)
——————— - ——————— + ————————
x - 7 x - 7 x - 7
Combine the numerators over the common
denominator:
(x + 2) - (x - 4) + (8x + 8)
————————————————————————————
x - 7
Remove the parentheses
x + 2 - x + 4 + 8x + 8
————————————————————————
x - 7
Combine like terms:
8x + 14
—————————
x - 7
Edwin