SOLUTION: Lane invested $22,000, part at 8% and part at 7%. If the total interest at the end of the year is $1,710, how much did she invest at 8%?

Algebra ->  Equations -> SOLUTION: Lane invested $22,000, part at 8% and part at 7%. If the total interest at the end of the year is $1,710, how much did she invest at 8%?      Log On


   



Question 45978: Lane invested $22,000, part at 8% and part at 7%. If the total interest at the end of the year is $1,710, how much did she invest at 8%?
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
0.08(x) + 0.07(22000 - x) = 1710
0.08x + 1540 - 0.07x = 1710
0.01x = 170
x = 17000
$17,000 in 8%