SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train A is traveling at 104 miles per hour. Train A passes a

Algebra ->  Equations -> SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train A is traveling at 104 miles per hour. Train A passes a      Log On


   



Question 459283: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train A is traveling at 104 miles per hour. Train A passes a station at 2:25 PM. If train B passes the same station at 2:55 PM, at what time will Train B catch up to Train A?

Answer by htmentor(1343) About Me  (Show Source):
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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per hour and Train A is traveling at 104 miles per hour. Train A passes a station at 2:25 PM. If train B passes the same station at 2:55 PM, at what time will Train B catch up to Train A?
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The RELATIVE speed of the two trains is 104 - 100 = 4 mph
Train A has a 30 min. head start, so when train B passes the station, they are this far apart:
100 mph * 0.5 h = 50 miles
At the relative speed of 4 mph, it will take this long to cover the 52 miles:
50 mi/4 mi/hr = 12.5 hrs
So the time will be 2:55 pm + 12.5 hrs = 3:25 am (the next day)