SOLUTION: If x/3 -1 is twice as large as x/4 -3 , what is the value of x?
I've tried:
x/3 - 1 = 2(x/4 -3)
x/3 -1 = 2x/8 - 6
x/3 = 2x/8 - 5
8x/24 = 2x-5
8x = 48x-5
5 = 40
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-> SOLUTION: If x/3 -1 is twice as large as x/4 -3 , what is the value of x?
I've tried:
x/3 - 1 = 2(x/4 -3)
x/3 -1 = 2x/8 - 6
x/3 = 2x/8 - 5
8x/24 = 2x-5
8x = 48x-5
5 = 40
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Question 458000: If x/3 -1 is twice as large as x/4 -3 , what is the value of x?
I've tried:
x/3 - 1 = 2(x/4 -3)
x/3 -1 = 2x/8 - 6
x/3 = 2x/8 - 5
8x/24 = 2x-5
8x = 48x-5
5 = 40x
x=8
but im not sure if its right. Please let me know the answer. Thanks! Answer by robertb(5830) (Show Source):
