Question 455684: Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b
(3,6); 8x+y=7
Can anyone help me understand this, I need help. Thank you so much
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b
(3,6); 8x+y=7
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Find the slope of the given line:
8x+y = 7
y = -8x+7
slope = -8
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ANY line perpendicular to the given line
must have a slope = 1/8.
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You want the equation of a line with
slope = 1/8 passing thru (3,6)
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Form: y = mx + b
Substitute for y,x,and m and solve for "b":
6 = (1/8)3 + b
6 = 3/8 + b
(48/8) = (3/8) + b
b = 45/8
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Equation:
y = (1/8)x + (45/8)
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cheers,
Stan H.
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