SOLUTION: Find a polynomial of lowest degree with only real coefficients and having the given zeros. 1+ square root of 3,1- square root of 3, and 7

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Question 45554: Find a polynomial of lowest degree with only real coefficients and having the given zeros.
1+ square root of 3,1- square root of 3, and 7

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
(x - (1 + sqrt(3))(x - (1 - sqrt(3))(x - 7)
(x - 1 - sqrt(3)(x - 1 + sqrt(3))(x - 7)
(x^2 - x - sqrt(3)x - x + 1 + sqrt(3) + sqrt(3)x - sqrt(3) - 3)(x - 7)
(x^2 - 2x - 2)(x - 7)
x^3 - 2x^2 - 2x - 7x^2 + 14x + 14
x^3 - 9x^2 + 12x + 14 = f(x)
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E3+-+9x%5E2+%2B+12x+%2B+14%29+