SOLUTION: Find an eaution of the line containing the given pair of points. ( - 7, - 9) and ( - 4, - 8)

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Question 454379: Find an eaution of the line containing the given pair of points.
( - 7, - 9) and ( - 4, - 8)

Found 2 solutions by mananth, ikleyn:
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
x1 y1 x2 y2
-7 -9 -4 -8

slope m =(y2-y1)/(x2-x1)
(-8+9)/(-4+7)
(1/3)
m=0.33

Plug value of the slope and point (-7,-9) in
Y =mx+b
-9.00=-2.33+b
b= -9-2.33
b= -6.67
So the equation will be
Y =0.33x-6.67
m.ananth@hotmail.ca

Answer by ikleyn(53547) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find an eqaution of the line containing the given pair of points.
(-7,-9) and (-4,-8)
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        The solution in the post by @mananth is incorrect both technically and methodologically.
        I came to bring a correct solution.


First find the slope of the line  

    m = %28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 = %28-8+-+%28-9%29%29%2F%28-4+-+%28-7%29%29 = %28-8%2B9%29%2F%28-4%2B7%29 = 1%2F3.


Notice that  -1%2F3  is not -0.33,  as @mananth mistakenly states and uses.


Plug the value of the slope and the values of the coordinates (-7,-9) of the given point  
in the point-slope equation of the line 

    y = mx + b,

    -9 = %281%2F3%29%2A%28-7%29 + b,

    b = -9 + 7%2F3 = %28-27%2B7%29%2F3 = -20%2F3 = -62%2F3.


So, an equation is

    y = %281%2F3%29x - 62%2F3.


It is the slope-intercept form equation.


Notice that it is absolutely different from that in the post by @mananth.

Solved correctly.