SOLUTION: Please solve the equation {{{3(n-1)^2+20=19(n-1)}}}

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Question 45098: Please solve the equation
3%28n-1%29%5E2%2B20=19%28n-1%29
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
3%28n+-+1%29%5E2+%2B+20+=+19%28n+-+1%29
3%28n%5E2+-+2n+%2B+1%29+%2B+20+=+19n+-+19
3n%5E2+-+6n+%2B+3+%2B+20+=+19n+-+19
3n%5E2+-+25n+%2B+42+=+0
3n%5E2+-+7n+-+18n+%2B+42+=+0
%283n%5E2+-+7n%29+%2B+%28-18n+%2B+42%29+=+0
n%283n+-+7%29+-+6%283n+-+7%29+=+0
%28n+-+6%29%283n+-+7%29+=+0
n = 6
and
n = 7/3