SOLUTION: m2-5m=0

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Question 448721: m2-5m=0
Answer by chriswen(106) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation am%5E2%2Bbm%2Bc=0 (in our case 1m%5E2%2B-5m%2B0+=+0) has the following solutons:

m%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-5%29%5E2-4%2A1%2A0=25.

Discriminant d=25 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--5%2B-sqrt%28+25+%29%29%2F2%5Ca.

m%5B1%5D+=+%28-%28-5%29%2Bsqrt%28+25+%29%29%2F2%5C1+=+5
m%5B2%5D+=+%28-%28-5%29-sqrt%28+25+%29%29%2F2%5C1+=+0

Quadratic expression 1m%5E2%2B-5m%2B0 can be factored:
1m%5E2%2B-5m%2B0+=+1%28m-5%29%2A%28m-0%29
Again, the answer is: 5, 0. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-5%2Ax%2B0+%29