SOLUTION: 3) The units digit is 3 times more the tens digit. When the digits are reversed, the new number is 54 more than the original.
4)The units digit is 3 times the tens digit. The n
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-> SOLUTION: 3) The units digit is 3 times more the tens digit. When the digits are reversed, the new number is 54 more than the original.
4)The units digit is 3 times the tens digit. The n
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Question 448333: 3) The units digit is 3 times more the tens digit. When the digits are reversed, the new number is 54 more than the original.
4)The units digit is 3 times the tens digit. The number is 12 more than 9 times the tens digit.
So the original number is then . The reversed digit number is (swap u and t). Ex: if t = 5 and u = 9, then the original number is 59 and the swapped number is 95.
Since "The units digit is 3 times more the tens digit", we know that (ie multiply the tens digit t by 3 to get the units digit u).
Now "When the digits are reversed, the new number is 54 more than the original", this means that
Start with the given equation.
Plug in (ie replace EVERY "u", without quotes, with "3t", without quotes)
Multiply
Combine like terms on the left side.
Combine like terms on the right side.
Subtract from both sides.
Combine like terms on the left side.
Divide both sides by to isolate .
Reduce.
So the tens digit is 3. Because we know that , we can plug this into that equation to get . So the units digit is 9
So the original number is 39. The new swapped number is 93. Notice how 93 is 54 more than 39 (ie 39+54 = 93)
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# 4
Use the same basic strategy to solve this problem. Let me know if you still need help.