SOLUTION: find 2n^2 if n(n+3)=4

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Question 447113: find 2n^2 if n(n+3)=4
Answer by htmentor(1343) About Me  (Show Source):
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n(n+3)=4
n^2 + 3n = 4
n^2 + 3n - 4 = 0
Solve for n using the quadratic formula:
n+=+%28-3+%2B-+sqrt%289+%2B+16%29%29%2F2
This gives n = 1,-4
So 2n^2 = 2 or 32