SOLUTION: 9x^2-16y^2 over xy all over 3 over y-4 over x wouldn't xy be your common denominator?

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Question 44527: 9x^2-16y^2 over xy all over 3 over y-4 over x
wouldn't xy be your common denominator?
Answer by gsmani_iyer(201) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
My answer to the problem No.44551 will clear your doubt. However, I am reproducing the same here below: Here %289x%5E2-16y%5E2%29%2Fxy will be taken as numerator and %283%2Fy%29-%284%2Fx%29 will be taken as denominator and simplified/factorised first.
%28%289x%5E2-16y%5E2%29%2Fxy%29%2F%28%283%2Fy%29-%284%2Fx%29%29 After factorising the numerator and simplifying the denominator, we get,

%28%283x%2B4y%29%283x-4y%29%2Fxy%29%2F%28%283x-4y%29%2Fxy%29. This means the numerator divided by the denominator. For dividing, we multiply the numerator by the inverse of the denominator. So,

%28%283x%2B4y%29%283x-4y%29%2Fxy%29%2A%28xy%2F%283x-4y%29%29%29 = %28%283x%2B4y%29%283x-4y%29xy%29%2F%28xy%2A%283x-4y%29%29 =

3x%2B4y Answer. I hope this is clear to you now.
gsm