SOLUTION: 18x^3-98x

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Question 442333: 18x^3-98x
Found 2 solutions by swincher4391, shree840:
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
Factor out a 2x.
2x(9x^2 -49)
Notice 9 and 49 are both perfect squares.
(3x)^2 = 9x^2
7^2 = 49
Since this is a difference of perfect squares, then 9x^2 - 49 = (3x+7)(3x-7)
Thus 2x%283x%2B7%29%283x-7%29 is your answer.

Answer by shree840(260) About Me  (Show Source):
You can put this solution on YOUR website!
18x^3-98x
=2x(9x^2-49)
=2x(3x+7)(3x-7) ans