SOLUTION: solve the following problem, be sure to show the equation used for the solution.
The lenght of a rectangle is 2in. more than twice its width. if the perimeter of the retangle i
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The lenght of a rectangle is 2in. more than twice its width. if the perimeter of the retangle i
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Question 44061: solve the following problem, be sure to show the equation used for the solution.
The lenght of a rectangle is 2in. more than twice its width. if the perimeter of the retangle is 34 in., find the dimensions of the rectangle. Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! solve the following problem, be sure to show the equation used for the solution.
The lenght....L SAY
of a rectangle is 2in. more than twice its width....W SAY
TWICE WIDTH =2W
2" MORE=2W+2
L=2W+2
PERIMETER=2(L+W)=2(2W+2+W)=34
3W+2=34/2=17
3W=17-2=15
W=15/3=5
L=2W+2=2*5+2=12
if the perimeter of the retangle is 34 in., find the dimensions of the rectangle.
