SOLUTION: I need help on the following: Find the solutions to the equation: x^2+2x+5=0. Thanks!

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Question 43653: I need help on the following: Find the solutions to the equation: x^2+2x+5=0. Thanks!
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
You will need to use the quadratic formula because this problem cannot be factored evenly.
Plug the values into the quadratic formula:
x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A1%2A5+%29%29%2F%282%2A1%29+
Simplify and solve the problem.
x+=+%28-2+%2B-+sqrt%28+4+-+20+%29%29%2F%282%29+
.
Continue to simplify:
x+=+%28-2+%2B-+sqrt%28+-16+%29%29%2F%282%29+
The square root of -16 = 4i
Since there is a (-1) under the radical sign, the answer will contain the imaginary number (i):
(-2 plus or minus 4i)/2
.
Factor out -2:
-2(1 plus or minus 2i)/2
.
Cancel out the 2's:
Answer: -1 plus or minus 2i