SOLUTION: 3 over a^2-9 + 2 over a+3 all over 4 over a^2 -9 + 1 over a+3 the answer is 2a-3 over a+1 show how you would get that

Algebra ->  Equations -> SOLUTION: 3 over a^2-9 + 2 over a+3 all over 4 over a^2 -9 + 1 over a+3 the answer is 2a-3 over a+1 show how you would get that      Log On


   

Question 43540: 3 over a^2-9 + 2 over a+3
all over
4 over a^2 -9 + 1 over a+3
the answer is 2a-3 over a+1
show how you would get that
Answer by gsmani_iyer(201) About Me  (Show Source):
You can put this solution on YOUR website!

%283%2F%28a%5E2-9%29%2B2%2F%28a%2B3%29%29%2F%284%2F%28a%5E2-9%29%2B1%2F%28a%2B3%29%29

Let us now take only the numerator and simplify it. So the numerator will be:
%283%2B2%28a-3%29%29%2F%28a%5E2-9%29 = %283%2B2a-6%29%2F%28a%5E2-9%29 = %282a-3%29%2F%28a%5E2-9%29

Similarly simplify the denominator as under:-

%284%2B1%28a-3%29%29%2F%28a%5E2-9%29 = %284%2Ba-3%29%2F%28a%5E2-9%29 = %28a%2B1%29%2F%28a%5E2-9%29

To further simplify, the numerator is to be divided by the denominator.
i.e. numerator is to be multiplied by the multiplicative inverse of the denominator.

%282a-3%29%2F%28a%5E2-9%29*%28a%5E2-9%29%2F%28a%2B1%29 = %282a-3%29%28a%5E2-9%29%2F%28%28a%5E2-9%29%28a%2B1%29%29 = %282a-3%29cross%28%28a%5E2-9%29%29%2F%28cross%28%28a%5E2-9%29%29%28a%2B1%29%29 = %282a-3%29%2F%28a%2B1%29 Answer.

That's all. I hope you have now understood how the answer has been arrived at.
gsm