SOLUTION: how to solve 2y(y+6)=32
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Question 433491
:
how to solve 2y(y+6)=32
Answer by
stanbon(75887)
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how to solve 2y(y+6)=32
--
y(y+6) = 16
y^2+6y-16 = 0
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Factor:
(y+8)(y-2) = 0
y = -8 or y = 2
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Cheers,
Stan H.