SOLUTION: Find the quadratic equation with integral coefficients having the given roots. 4 + 2i, 4 - 2i Thanks!!

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Question 431282: Find the quadratic equation with integral coefficients having the given roots.
4 + 2i, 4 - 2i
Thanks!!

Found 2 solutions by robertb, richard1234:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The coefficient of x is equal to -(4 + 2i + 4- 2i) = -8.
The constant term is equal to (4+2i)(4-2i) = 16 - 4(-1) = 20.
Hence the quadratic equation is x%5E2+-+8x+%2B+20+=+0.

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
The quadratic will have x+-+%284%2B2i%29+=+x+-+4+-+2i and x+-+%284-2i%29+=+x+-+4+%2B+2i as factors. Hence, the quadratic is equal to (applying the difference of two squares)

Expanding and simplifying, this is equal to x%5E2+-+8x+%2B+16+%2B+4+=+x%5E2+-+8x+%2B+20.