SOLUTION: 1. f(x)= x^3 - 3x^2 + x + 1 2. f(x)=sinx + 1 on [-2pi, 2pi] 3. f(x)=(x^2)(e^(-4x)) (a) Find the x- and y-intercepts of the function. (b) Draw a number line for f: (c) Find a

Algebra ->  Equations -> SOLUTION: 1. f(x)= x^3 - 3x^2 + x + 1 2. f(x)=sinx + 1 on [-2pi, 2pi] 3. f(x)=(x^2)(e^(-4x)) (a) Find the x- and y-intercepts of the function. (b) Draw a number line for f: (c) Find a      Log On


   



Question 428180: 1. f(x)= x^3 - 3x^2 + x + 1
2. f(x)=sinx + 1 on [-2pi, 2pi]
3. f(x)=(x^2)(e^(-4x))
(a) Find the x- and y-intercepts of the function.
(b) Draw a number line for f:
(c) Find all critical numbers for f prime:
(d) Draw a number line for f prime:
(e) Find all zeros of f double prime:
(f) Draw a number line for f double prime:
(h) Find all inflection points of f:
(i) Sketch the graph of f. Label all inflection points. Label your axes.

Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
I'll get you started:

If f(x) = x%5E3+=+3x%5E2+%2B+x+%2B+1, then f'(x) = 3x%5E2+%2B+1 and f''(x) = 6x (simply applying the power rule).
If f(x) = sin%28x%29%2B1 then f'(x) = cos%28x%29 and f''(x) = -sin%28x%29.
#3 is a little harder to differentiate because we need to apply the product rule twice. If f(x) = %28x%5E2%29%28e%5E%28-4x%29%29 then f'(x) = 2x%28e%5E%28-4x%29%29+-+4%28x%5E2%29%28e%5E%28-4x%29%29+=+e%5E%28-4x%29%282x+-+4x%5E2%29. Differentiating again, f''(x) = . I'll let you handle the 24 parts of the problem.