SOLUTION: Solve the following system of equations using substitution.
2x+4y=12
4x+16y=8
I substituted 2x+4y for x in the second equation and I ended up with 8x+32y=8. I've tried so ma
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-> SOLUTION: Solve the following system of equations using substitution.
2x+4y=12
4x+16y=8
I substituted 2x+4y for x in the second equation and I ended up with 8x+32y=8. I've tried so ma
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Question 427061: Solve the following system of equations using substitution.
2x+4y=12
4x+16y=8
I substituted 2x+4y for x in the second equation and I ended up with 8x+32y=8. I've tried so many of these problems and I just can't understand them. Found 2 solutions by ewatrrr, Gogonati:Answer by ewatrrr(24785) (Show Source):
Hi
Note: the idea solving using substitution is for that to result
in an equation with ONE unknown.
2x+4y=12 OR x = 6-2y |solving for x
4x+16y=8 |Substituting that into the 2nd EQ
4(6-2y)+16y = 8 |now we have an EQ with ONE unknown
solving for y
24 - 8y + 16y = 8
8y = -16
y = -2 and x = 10 (6- 2*-2)
CHECKING our Answer***
4x+16y=8
40 -32=8
You can put this solution on YOUR website! Solution:First we simplify the system dividing the first equation by 2 and the second by 4,and the system can be written:
, Express x in the first equation with respect to y and substitute in the second equation:
The second equation is a linear equation of one variable. We solve this equation with respect to y:
6+2y=2 => 2y=-4 => y=-2. Substitute this value of y in the first equation and find x: x=6-2(-2) => x=10. The ordered pair (10, -2) is the solution of our system.
