SOLUTION: Given that the equation of a circle is x^2 + y^2 - 10x + 4y + 13=0,find its center and its radius.

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Question 41139This question is from textbook Algebra and Trigonometry
: Given that the equation of a circle is x^2 + y^2 - 10x + 4y + 13=0,find its center and its radius. This question is from textbook Algebra and Trigonometry

Answer by venugopalramana(3286) About Me  (Show Source):
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Given that the equation of a circle is x^2 + y^2 - 10x + 4y + 13=0,find its center and its radius.
(X^2-2*X*5+5^2)+(Y^2+2*Y*2+2^2)-5^2-2^2+13=0
(X-5)^2+(Y+2)^2=25+4-13=16=4^2
COMPARING WITH STD.EQN.OF CIRCLE
(X-H)^2+(Y-K)^2=R^2
CENTRE IS (H,K)......(5,-2)
RADIUS=R =4