SOLUTION: when a ball is thrown up into the air it makes a shape of a parabola the equation s=-16t^2+v*t+k gives the height of the ball at any time, t in seconds where v is the initial veloc

Algebra ->  Equations -> SOLUTION: when a ball is thrown up into the air it makes a shape of a parabola the equation s=-16t^2+v*t+k gives the height of the ball at any time, t in seconds where v is the initial veloc      Log On


   

Question 411053: when a ball is thrown up into the air it makes a shape of a parabola the equation s=-16t^2+v*t+k gives the height of the ball at any time, t in seconds where v is the initial velocity speed in ft/sec and k is the initial height in feet as if you were on top of a tower or building make a scenario where a ball is thrown,shot,etc into the air. you can choose any initial velocity in ft/sec and any initial height in feet the ball but include them in your scenario
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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when a ball is thrown up into the air it makes a shape of a parabola the equation
s=-16t^2+v*t+k gives the height of the ball at any time, t in seconds where v is
the initial velocity speed in ft/sec and k is the initial height in feet as if
you were on top of a tower or building make a scenario where a ball is thrown, shot,etc into the air.
you can choose any initial velocity in ft/sec and any initial height in feet the ball but include them in your scenario
:
Let v = 32 ft/sec speed of the the thrown ball upward
Let k = 128 ft, height of building
:
s = -16t^2 + 32t + 128
:
Graphically
+graph%28+300%2C+200%2C+-3%2C+6%2C+-50%2C+180%2C+-16x%5E2%2B32x%2B128%29+
:
max height at 1 sec, hits the ground in 4 sec