SOLUTION: equation of the line in slope-intercept (4,0),(-2,1) )

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Question 407557: equation of the line in slope-intercept

(4,0),(-2,1) )

Answer by MathLover1(20849) About Me  (Show Source):
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (4, 0) and (x2, y2) = (-2, 1).
Slope a is .
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -0.166666666666667%2A4+%2Bb+=+0.666666666666667. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0--0.166666666666667%2A4+=+0.666666666666667.

y=(-0.166666666666667)x + (0.666666666666667)

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