SOLUTION: (x^2+6x+9)/(x^2-9) what numbers are excluded

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Question 407524: (x^2+6x+9)/(x^2-9) what numbers are excluded
Answer by jim_thompson5910(35256) About Me  (Show Source):
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You CANNOT divide by zero. So this means that the denominator x%5E2-9 CANNOT be equal to zero. So if x%5E2-9 were zero, then x%5E2-9=0 and we'd find that x=3 or x=-3.


So if x=3 or x=-3, then the denominator is zero. This is not allowed. So we must make the restrictions that x cannot equal 3 or x cannot equal -3.


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