SOLUTION: find the slope intercept form of the equation of the line that passs thought (-1,5)and is parallel to 4x+2y=8

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Question 404753: find the slope intercept form of the equation of the line that passs thought (-1,5)and is parallel to 4x+2y=8
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

find the slope intercept form of the equation of the line that passes thought (-1%2C5)and is parallel to 4x%2B2y=8
first find the slope of this line:
4x%2B2y=8......write it in slope-intercept form...or solve for y
2y=+-+4x+%2B+8.......both sides divide by 2
2y%2F2=+-+4x%2F2+%2B+8%2F2
y=+-2x+%2B+4.........as you can see, slope is -2
since the line that passes thought (-1%2C5) is parallel to given line, should have same slope
now, we have slope m=-2 and point (-1%2C5) and we can find the equation of the line that passes thought

Solved by pluggable solver: FIND a line by slope and one point

What we know about the line whose equation we are trying to find out:

  • it goes through point (-1, 5)

  • it has a slope of -2



First, let's draw a diagram of the coordinate system with point (-1, 5) plotted with a little blue dot:



Write this down: the formula for the equation, given point x%5B1%5D%2C+y%5B1%5D and intercept a, is

y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29 (see a paragraph below explaining why this formula is correct)

Given that a=-2, and system%28+x%5B1%5D+=+-1%2C+y%5B1%5D+=+5+%29+, we have the equation of the line:

y=-2%2Ax+%2B+3

Explanation: Why did we use formula y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29 ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (x%5B1%5D, y%5B1%5D) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (x%5B1%5D, y%5B1%5D): y%5B1%5D+=+a%2Ax%5B1%5D%2Bb Here, we know a, x%5B1%5D, and y%5B1%5D, and do not know b. It is easy to find out: b=y%5B1%5D-a%2Ax%5B1%5D. So, then, the equation of the line is: +y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+.

Here's the graph:





now, let see a graph with both lines on it:
y=+-2x+%2B+4
y=-2x%2B3

+graph%28+500%2C500%2C+-10%2C+10%2C+-10%2C+10%2C+-2x+%2B+4%2C-2x%2B3%29+