SOLUTION: I am doing pythagorean theorem. I am trying to solve for x A:x B: X+7 C: 13 I have completed the problem to 2x^2 + 14x-120=0 What is the next step to solve for x?

Algebra ->  Equations -> SOLUTION: I am doing pythagorean theorem. I am trying to solve for x A:x B: X+7 C: 13 I have completed the problem to 2x^2 + 14x-120=0 What is the next step to solve for x?      Log On


   

Question 403424: I am doing pythagorean theorem. I am trying to solve for x
A:x
B: X+7
C: 13
I have completed the problem to
2x^2 + 14x-120=0
What is the next step to solve for x?
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Divide both sides by 2 to get x%5E2+%2B+7x+-+60+=+0. Luckily, this factors to %28x+-+5%29%28x+%2B+12%29+=+0 --> x = 5 or x = -12. We take the positive solution x = 5, and get a right triangle with lengths 5, 12, 13.