SOLUTION: It has been 20+ years and algebra still makes me phisically sick. I am stumped on the silliest of things. 1/3(2a-8)-7 = 2/5a The common denominator (as far as I can tell) is

Algebra ->  Equations -> SOLUTION: It has been 20+ years and algebra still makes me phisically sick. I am stumped on the silliest of things. 1/3(2a-8)-7 = 2/5a The common denominator (as far as I can tell) is      Log On


   



Question 40064This question is from textbook Aplied Algebra & Trig
: It has been 20+ years and algebra still makes me phisically sick. I am stumped on the silliest of things.
1/3(2a-8)-7 = 2/5a
The common denominator (as far as I can tell) is 15, then each term gets * by the common denom...
so does that mean?
15/3(30a-8)-105 = 15/5a
This question is from textbook Aplied Algebra & Trig

Answer by atif.muhammad(135) About Me  (Show Source):
You can put this solution on YOUR website!
+%282a-8%29%2F3+-+7+=+2%2F5a

+%282a-8%29%2F3+-+7%2F1+=+2%2F5a

Make the denominator of 7%2F1 the same as the denominator of %282a-8%29%2F3.

Just times 7%2F1 but some number to get its denominator to 3. In this case, we just times 1 (the denominator by 3 in order to get its overall denominator to 3.

Whatever we do the the denominator, must also be done to the numerator. We have times the denominator by 3 and therefore, we must also times the numerator by 3.

We end up with 21%2F3

Now we have:

%282a-8%29%2F3+-+21%2F3+=+2%2F5a

We can join up the fractions on the left hand side as they have common denominators.

+%282a-8-21%29%2F3+=+2%2F5a

This gives us:

+%282a-29%29%2F3+=+2%2F5a

Whenever we get this in maths, (a technique I have always used), we cross multiply.

So from, +%282a-29%29%2F3+=+2%2F5a

We get,

+%282a-29%29%285a%29+=+2+x+3+

We can now multiply out the brackets.

+10a%5E2+-+145a+=+6

Rearrange the equation:

10a%5E2+-+145a+-+6+=+0

This is a quadratic equation.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 10x%5E2%2B-145x%2B-6+=+0) has the following solutons: x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number. First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-145%29%5E2-4%2A10%2A-6=21265. Discriminant d=21265 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--145%2B-sqrt%28+21265+%29%29%2F2%5Ca. x%5B1%5D+=+%28-%28-145%29%2Bsqrt%28+21265+%29%29%2F2%5C10+=+14.5412618935271 x%5B2%5D+=+%28-%28-145%29-sqrt%28+21265+%29%29%2F2%5C10+=+-0.0412618935270729 Quadratic expression 10x%5E2%2B-145x%2B-6 can be factored: 10x%5E2%2B-145x%2B-6+=+10%28x-14.5412618935271%29%2A%28x--0.0412618935270729%29 Again, the answer is: 14.5412618935271, -0.0412618935270729. Here's your graph: graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+10%2Ax%5E2%2B-145%2Ax%2B-6+%29
x = 14.5412618935271, -0.0412618935270729