SOLUTION: Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station
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Question 397057: Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?
(Can you inclede in the answer, either A.M. or P.M, thanks)! Found 3 solutions by Edwin McCravy, josmiceli, stanbon:Answer by Edwin McCravy(20055) (Show Source):
You can put this solution on YOUR website! Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?
(Can you include in the answer, either A.M. or P.M, thanks)!
Some teachers do not like for you to use approach-rate when one thing is
catching up to another, and separation rate when two things are going apart in
opposite directions. But I will, because it's often easier. In fact using
approach rate, you can do this one in your head.
approach rate = the difference of the speeds
separation rate = sum of the speeds
This problem uses approach rate of 88-80 = 8 mph. Here goes:
During the hour (15 minutes) between 6:25PM and 6:40PM, train A has gone
of 80 miles or 20 miles from the station. So A has a 20 mile head start on
B at the time B leaves the station. Then B's approach rate is 88-80 or 8 miles
per hour. Since time = distance/rate, it will take B or or hours, So
2 and a half hours from 6:40PM will be 9:10PM.
Edwin
You can put this solution on YOUR website!
Train B passes the station at 6:40 PM. I know that train A
passed the station 15 min ago at 6:25 PM.
In 15 min, train A has travelled mi
Let = distance train B has to go to catch train A.
Then is the distance train A must go to
meet B.
For train A:
For train B:
Substitute in 2nd equation into 1st equation hr
train B will catch train A in 2.5 hrs after train B passed station.
6:40 PM + 2.5 = 9:10 PM
You can put this solution on YOUR website! Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?
(Can you inclede in the answer, either A.M. or P.M, thanks)!
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Train A DATA:
rate = 80 mph ; time = x minutes ; distance = (x/60)(80) = (4/3)x miles
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Train B DATA:
rate = 88 miles; time = (x-15) minutes; distance = [(x-15)/60]88 miles
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Equation:
distance = distance
(4/3)x = (88/60)(x-15)
Multiply both sides by 60 to get
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80x = 88(x-15)
80x = 88x-88*15
8x = 88*15
x = 11*15
x = 161 minutes = 2 hrs 41 minutes
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6:25PM + 2hrs 41 minutes = 9:05 PM
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Cheers,
Stan H.