SOLUTION: Please help me solve {{{ -0.2x^2+12x+11 }}}

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Question 393550: Please help me solve +-0.2x%5E2%2B12x%2B11+
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
+-0.2x%5E2%2B12x%2B11+
...
solve by quadratic formula
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
a=-0.2,b=12,c=11
b^2-4ac=152.8
x1=%28-%2812%29%2Bsqrt%28152.8%29%29%2F%28-0.4%29
x1=-0.90
x2=%28-%2812%29-sqrt%28152.8%29%29%2F-0.4
x2=60.90
..
m.ananth@hotmail.ca