SOLUTION: 1. Solve algebraically the equation 15sin2x°=10cosx° for 0&#8804;x<360.

Algebra ->  Equations -> SOLUTION: 1. Solve algebraically the equation 15sin2x°=10cosx° for 0&#8804;x<360.       Log On


   

Question 388618: 1. Solve algebraically the equation 15sin2x°=10cosx° for 0≤x<360.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve algebraically the equation
15sin(2x)°=10cos(x)° for 0≤x<360.
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sin(2x)/cos(x) = 2/3
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(2sin(x)(cos(x))/cos(x) = 2/3
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2sin(x) = 2/3
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sin(x) = (1/3)
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x = sin^1(1/3) = 19.47 degrees or 180-19.47 = 160.53 degrees
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Cheers,
Stan H.