SOLUTION: -3(b-8)-5=9(b+2)+1 I tried -3b+24-5=9b+18+1 -3b+19=9b+19 -3b=9b

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Question 380014: -3(b-8)-5=9(b+2)+1
I tried
-3b+24-5=9b+18+1
-3b+19=9b+19
-3b=9b
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
-3%28b-8%29-5=9%28b%2B2%29%2B1 Start with the given equation.


-3b%2B24-5=9b%2B18%2B1 Distribute.


-3b%2B19=9b%2B18%2B1 Combine like terms on the left side.


-3b%2B19=9b%2B19 Combine like terms on the right side.


-3b=9b%2B19-19 Subtract 19 from both sides.


-3b-9b=19-19 Subtract 9b from both sides.


-12b=19-19 Combine like terms on the left side.


-12b=0 Combine like terms on the right side.


b=%280%29%2F%28-12%29 Divide both sides by -12 to isolate b.


b=0 Reduce.


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Answer:

So the solution is b=0


Note: this is what you would have gotten if you continued.


If you need more help, email me at jim_thompson5910@hotmail.com

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Jim