SOLUTION: find the solution of the following differential equations: 1. dy/dx= te^y, y(1)=0 2. x^2y'+2xy=cosx

Algebra ->  Equations -> SOLUTION: find the solution of the following differential equations: 1. dy/dx= te^y, y(1)=0 2. x^2y'+2xy=cosx      Log On


   

Question 378889: find the solution of the following differential equations:
1. dy/dx= te^y, y(1)=0
2. x^2y'+2xy=cosx
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1. Is t a constant?
Or should that be an x.
.
.
.
2. x%5E2%2A%28dy%2Fdx%29%2B2xy=cos%28x%29
x%5E2y=sin%28x%29%2BC