SOLUTION: Hello, I recently took an assessment and now I'm doing a test revision. This is one of the problems I got wrong: 6(2y+5)-4(y-3)=7 Can you help me solve the equation for y? I

Algebra ->  Equations -> SOLUTION: Hello, I recently took an assessment and now I'm doing a test revision. This is one of the problems I got wrong: 6(2y+5)-4(y-3)=7 Can you help me solve the equation for y? I       Log On


   

Question 374754: Hello, I recently took an assessment and now I'm doing a test revision. This is one of the problems I got wrong:
6(2y+5)-4(y-3)=7
Can you help me solve the equation for y? I tried and got 25 over 8 (as in a fraction), but I don't remember what I did, because the test was almost 3 weeks ago.
Thanks in advance.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
6%282y%2B5%29-4%28y-3%29=7 Start with the given equation.


12y%2B30-4y%2B12=7 Distribute.


8y%2B42=7 Combine like terms on the left side.


8y=7-42 Subtract 42 from both sides.


8y=-35 Combine like terms on the right side.


y=%28-35%29%2F%288%29 Divide both sides by 8 to isolate y.


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Answer:

So the solution is y=-35%2F8


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim