SOLUTION: Solve the equation over the interval [0 pi, 2 pi) : 3tan^3x=tanx

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Question 371832: Solve the equation over the interval [0 pi, 2 pi) : 3tan^3x=tanx
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
3%28tanx%29%5E3+-+tanx+=+0,
tanx%283%28tanx%29%5E2+-+1%29+=+0,
tanx = 0, or %28tanx%29%5E2+=+1%2F3, or
tanx = 0, or tanx+=+1%2Fsqrt%283%29 or tanx+=+-1%2Fsqrt%283%29.
therefore
x = 0, pi, pi%2F6, 7pi%2F6, 5pi%2F6, 11pi%2F6.