SOLUTION: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles

Algebra ->  Equations -> SOLUTION: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles      Log On


   



Question 37018: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Letting x be the speed
The word after in this problem is the key word to look for.
After means plus and before means subbtract
EQUATION:
6(x+3)=10x
4x=18
x=4.5
Hence, about 4.5 hours will pass.
Paul.