SOLUTION: During a chemical reaction, the temperature in the beaker decreased every minute by the same number of degrees. The temperature was 16°C at 11:08 A.M. By 11:43 A.M., the temperatur

Algebra ->  Equations -> SOLUTION: During a chemical reaction, the temperature in the beaker decreased every minute by the same number of degrees. The temperature was 16°C at 11:08 A.M. By 11:43 A.M., the temperatur      Log On


   



Question 362390: During a chemical reaction, the temperature in the beaker decreased every minute by the same number of degrees. The temperature was 16°C at 11:08 A.M. By 11:43 A.M., the temperature had dropped to -17°C. By how many degrees did it drop each minute?
the answer I came up with was 1.06 but i have no clue

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
it reduses by 16-(-17) = 33 degrees
time = 35 minutes
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35 minutes 33 degrees
1 minute ?
33/35 = 0.94/minute
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m.ananth@hotmail.ca
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