SOLUTION: 4x2+5x+6=0 كيف تم حساب نقطة الإنعطاف في &

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Question 360341: 4x2+5x+6=0
كيف تم حساب نقطة الإنعطاف في الرسم البياني
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

4x%5E2%2B5x%2B6=0 Start with the given equation.


Notice that the quadratic 4x%5E2%2B5x%2B6 is in the form of Ax%5E2%2BBx%2BC where A=4, B=5, and C=6


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%285%29+%2B-+sqrt%28+%285%29%5E2-4%284%29%286%29+%29%29%2F%282%284%29%29 Plug in A=4, B=5, and C=6


x+=+%28-5+%2B-+sqrt%28+25-4%284%29%286%29+%29%29%2F%282%284%29%29 Square 5 to get 25.


x+=+%28-5+%2B-+sqrt%28+25-96+%29%29%2F%282%284%29%29 Multiply 4%284%29%286%29 to get 96


x+=+%28-5+%2B-+sqrt%28+-71+%29%29%2F%282%284%29%29 Subtract 96 from 25 to get -71


x+=+%28-5+%2B-+sqrt%28+-71+%29%29%2F%288%29 Multiply 2 and 4 to get 8.


x+=+%28-5+%2B-+i%2Asqrt%2871%29%29%2F%288%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%28-5%2Bi%2Asqrt%2871%29%29%2F%288%29 or x+=+%28-5-i%2Asqrt%2871%29%29%2F%288%29 Break up the expression.


So the solutions are x+=+%28-5%2Bi%2Asqrt%2871%29%29%2F%288%29 or x+=+%28-5-i%2Asqrt%2871%29%29%2F%288%29