SOLUTION: the perimiter of a rectangle is 78 feet. can you help me find the dimensions? width 2x-4 length 2x+3

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Question 343662: the perimiter of a rectangle is 78 feet. can you help me find the dimensions?
width
2x-4
length
2x+3
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
PerimeterOfRectangle+=+2%2ALength+%2B+2%2Awidth
78+=+2%2A%282x%2B3%29+%2B+2%2A%282x-4%29
78+=+4x+%2B+6+%2B+4x+-+8
78+=+8x+-2
80+=+8x
10+=+x
If x = 10, then
Width+=+2%2A10+-4
Width+=+20-4
Width+=+16
Length+=+2%2A10+%2B+3
Length+=+20%2B3
Length+=+23
Check your answer
Does 23+23+16+16 = 78????